document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=929629>Question 929629</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many milliliters of a 10% hydrogen peroxide solution and how many milliliters of a 2% hydrogen peroxide solution should be mixed to obtain 500 mL if a 4% hydrogen peroxide solution?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #564398 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=564398\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how many milliliters of a 10% hydrogen peroxide solution and how many milliliters of a 2% hydrogen peroxide solution should be mixed to obtain 500 mL if a 4% hydrogen peroxide solution?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "hydro + hydro = hydro<BR>\n" );
document.write( "0.02x + 0.10(500-x) = 0.04*500<BR>\n" );
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document.write( "2x + 10*500 - 10x = 4*500<BR>\n" );
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document.write( "-8x = -6*500<BR>\n" );
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document.write( "x = (3/4)500<BR>\n" );
document.write( "x = 3*125 = 375 ml (amt. of 2% solution needed)<BR>\n" );
document.write( "500-x = 125 ml (amt. of 10% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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