document.write( "Question 929554: The length of a rectangle is 6 more than two times a number. The width is the number plus three and the area is 32. What is the width of the rectangle? \r
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Algebra.Com's Answer #564381 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "The length of a rectangle is 6 more than two times a number. The width is the number plus three and the area is 32. What is the width of the rectangle?
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Let number be N
\n" ); document.write( "Then length = 2N + 6, and width = N + 3
\n" ); document.write( "Since area = 32, then we get: (2N + 6)(N + 3) = 32
\n" ); document.write( "\"2N%5E2+%2B+12N+%2B+18+=+32\" ------- FOILing left side
\n" ); document.write( "\"2N%5E2+%2B+12N+%2B+18+%96+32+=+0\"
\n" ); document.write( "\"2N%5E2+%2B+12N+-+14+=+0\"
\n" ); document.write( "\"2%28N%5E2+%2B+6N+-+7%29+=+2%280%29\" ------- Factoring out GCF, 2
\n" ); document.write( "\"N%5E2+%2B+6N+-+7+=+0\"
\n" ); document.write( "(N - 1)(N + 7) = 0
\n" ); document.write( "N = 1 OR N = - 7 (ignore)
\n" ); document.write( "Width: 1 + 3, or \"highlight_green%284%29\" units
\n" ); document.write( "You can do the check!!
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