document.write( "Question 929567: if f(x)= 9/ (x-6) and g(x)= 3/x, find (f o g)(x) and the domain of f o g.
\n" ); document.write( "I got 3/(1-2x) but im not sure if thats correct. can you simplify it further? and for my domain i got (x cannot equal o,6,.5,) im pretty sure i did the domain incorrectly. Please help!
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Algebra.Com's Answer #564356 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You should have \"%283x%29%2F%281-2x%29\" for your (f o g)(x) when everything is completely simplified. \r
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\n" ); document.write( "\n" ); document.write( "You'll find that x cannot be zero (due to the division by zero error in g(x)) and that x cannot be 1/2 (due to the division by zero error in (f o g)(x)). \r
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\n" ); document.write( "\n" ); document.write( "It turns out that x = 6 works just fine in both g(x) and (f o g)(x), so x = 6 is allowed in the domain of the composite function.\r
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\n" ); document.write( "\n" ); document.write( "The value x = 6 doesn't work in f(x), but that doesn't matter as the x-6 turns into 1-2x when we get to (f o g)(x).
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