document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=929561>Question 929561</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The second angle of a triangle is 5° smaller than the first. The third angle is triple the size of the first angle. Use the letter F </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #564355 by </B><A HREF=/tutors/aboutme.mpl?userid=sunny1992><B>sunny1992(35)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sunny1992><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sunny1992><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=564355\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sum of all angle of triangle = 180° <BR>\n" );
document.write( "let,<BR>\n" );
document.write( "1st angle= F° <BR>\n" );
document.write( "2nd angle= F°-5°<BR>\n" );
document.write( "3rd anle= 3F° <BR>\n" );
document.write( "equation<BR>\n" );
document.write( "F°+(F°-5°)+3F° =180° <BR>\n" );
document.write( "5F°-5°=180°<BR>\n" );
document.write( "5f°=185°<BR>\n" );
document.write( "F°=185°/5°<BR>\n" );
document.write( "F°=  37° </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );