document.write( "Question 929272: (Tan^2)/secx))= secx-cosx\r
\n" ); document.write( "\n" ); document.write( "I seen in a video of a teacher transforming tan^2x into (sec^2x-1)/secx)) but how is that possible 1+tan^2x=sec^2x? How did the 1 go negative? How do you solve it with tanx=sinx/cosx as well? Sorry im asking for too much. \n" ); document.write( "

Algebra.Com's Answer #564336 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
(Tan^2)/secx))= secx-cosx
\n" ); document.write( "I seen in a video of a teacher transforming tan^2x into (sec^2x-1)/secx)) but how is that possible 1+tan^2x=sec^2x? How did the 1 go negative? How do you solve it with tanx=sinx/cosx as well? Sorry im asking for too much.
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\n" ); document.write( " $\"tan%5E2%28x%29=%28sin%5E2%28x%29%2Fcos%5E2%28x%29%29\"$
\n" ); document.write( "

\n" ); document.write( "or
\n" ); document.write( "1+tan^2(x)=sec^2(x) \n" ); document.write( "

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