document.write( "Question 929310: 1. You have deposited $7,000 in an account that pays 6.25% interest compounded continuously. How long will it take your money to double?\r
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\n" ); document.write( "\n" ); document.write( "2. You have deposited $12,000 in an account compounded monthly. After 7 years the balance has grown to $15,532. Find the rate.\r
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\n" ); document.write( "\n" ); document.write( "PLEASE HELP ME ANSWER THESE 2 QUESTIONS!!!
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Algebra.Com's Answer #564307 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
1. For continuous compounding, the balance amount \"A\" is related to
\n" ); document.write( "the principal (initial investment \"P\" ,
\n" ); document.write( "the rate \"r\" (written as a decimal), and
\n" ); document.write( "the time in years, \"t\" , by the formula
\n" ); document.write( "\"A=P%2Ae%5E%28%28r%2At%29%29\" .
\n" ); document.write( "The number \"e\" is an irrational number like \"pi\" that come up pretty often . It is not invented to make students learn one more number; it just comes up naturally.
\n" ); document.write( "We use it as a base for powers, and of course for logarithms that we call natural logarithms
\n" ); document.write( "\"6.25%25=6.25%2F100=0.0625\"
\n" ); document.write( "So, for \"P=7000\" , \"r=0.0625\" , and \"A=2%2AP=2%2A7000\" , we can write
\n" ); document.write( "\"2%2AP=P%2Ae%5E0.0625t\" ---> \"2=e%5E0.0625t\"
\n" ); document.write( "Note that we did not need to know the amount invested.
\n" ); document.write( "\"2=e%5E0.0625t\" ---> \"ln%282%29=0.0625t\" (taking natural logarithms on both sides).
\n" ); document.write( "Using the approximate value \"ln%282%29=0.693147\" ,
\n" ); document.write( "\"0.0625t=0.693147\"-->\"t=0.693147%2F.0625\"-->\"t=11.09\" (rounded).
\n" ); document.write( "So, it will take 11 years for the money to double.\r
\n" ); document.write( "\n" ); document.write( "2. $12,000 compounded monthly. After 7 years the balance has grown to $15,532. Find the rate.
\n" ); document.write( "For monthly compounding, the balance grow by \"%281%2F12%29\" of the yearly rate every month.
\n" ); document.write( "So over \"7years=7%2A12months=84months\", the balance grew by a factor of \"1%2B%28rate%2F12%29\" applied \"84\" times to
\n" ); document.write( "\"15320=12000%2A%281%2Brate%2F12%29%5E84\" .
\n" ); document.write( "Solving for rate:
\n" ); document.write( "\"15320=12000%2A%281%2Brate%2F12%29%5E84\"
\n" ); document.write( "\"15320%2F12000=%281%2Brate%2F12%29%5E84\"
\n" ); document.write( "\"1.2766666667=%281%2Brate%2F12%29%5E84\"
\n" ); document.write( "\"log%281.2766666667%29=84%2Alog%281%2Brate%2F12%29\"
\n" ); document.write( "\"%281%2F84%29%2Alog%281.2766666667%29=log%281%2Brate%2F12%29\"
\n" ); document.write( "Using logarithm base 10 for an approximate calculation:
\n" ); document.write( "\"%281%2F84%29%2A0.10677519=log%281%2Brate%2F12%29\"
\n" ); document.write( "\"0.0012628=log%281%2Brate%2F12%29\"
\n" ); document.write( "Reversing the logarithm by calculating power of 10 on both sides of the equal sign:
\n" ); document.write( "\"10%5E0.0012628=1%2Brate%2F12\"
\n" ); document.write( "\"1.002912=1%2Brate%2F12\"
\n" ); document.write( "\"1.002912-1=rate%2F12\"
\n" ); document.write( "\"0.002912=rate%2F12\"
\n" ); document.write( "\"rate=0.03496=%223.494%25%22\"
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