document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=78691>Question 78691</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0072549017/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> 7(x-3)>5x-14 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #56430 by </B><A HREF=/tutors/aboutme.mpl?userid=Septimus314><B>Septimus314(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Septimus314><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=56430\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Simplify left side, distribute out the 7.<BR>\n" );
document.write( "7x - 21 > 5x - 14\r<BR>\n" );
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document.write( "Get the x's on one side, and the rest on the other side.\r<BR>\n" );
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document.write( "-5x to both sides, and add 21 to both sides\r<BR>\n" );
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document.write( "2x > 7\r<BR>\n" );
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document.write( "Solving for x I presume, so divide both sides by 2 to get x on one side.\r<BR>\n" );
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document.write( "x > 7/2, or 3.5 </SPAN>\n" );
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