document.write( "Question 929437: 11.
\n" ); document.write( "If z represents a standard normal random variable, then the P(z ≥ - 0.44) is approximately
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\n" ); document.write( " A .3300
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\n" ); document.write( " B .6700
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\n" ); document.write( " C .1700
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\n" ); document.write( " D .44
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\n" ); document.write( " E .56
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Algebra.Com's Answer #564294 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!
P(z ≥ - 0.44) = normalcdf(-.44, 100) = .6700
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