document.write( "Question 929438: If z represents a standard normal random variable, then the P( -0.16 ≤ z ≤ 2.18) is approximately
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document.write( " A .04
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document.write( " B .42
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document.write( " C .48
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document.write( " D .49
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document.write( " E .55 \n" );
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Algebra.Com's Answer #564293 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! P( -0.16 ≤ z ≤ 2.18) = normalcdf(-.16, 2.18) = .5489 0r 54.89 \n" ); document.write( "E \n" ); document.write( " |