document.write( "Question 929413: The wait time for a company before a customer can talk to a customer service representative has a mean of 140 seconds with a standard deviation of 20 seconds. Suppose the distribution of wait times is approximately bell-shaped and symmetric.\r
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\n" ); document.write( "\n" ); document.write( "Which one of the following statements is correct?
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\n" ); document.write( "\n" ); document.write( " A The proportion of customers whose wait time is under 120 seconds is approximately 68%
\n" ); document.write( " B The proportion of customers whose wait time is under 120 seconds is approximately 95%
\n" ); document.write( " C The proportion of customers whose wait time is more than 160 seconds is approximately 84%
\n" ); document.write( " D The proportion of customers whose wait time is more than 160 seconds is approximately 16%
\n" ); document.write( " E The proportion of customers whose wait time is more than 140 seconds is greater than the proportion whose wait time is under 140 seconds
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Algebra.Com's Answer #564262 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
mean =140sec, SD = 20 seconds, \"z+=+blue%28x+-+140%29%2Fblue%2820%29\"
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\n" ); document.write( "P(x < 120) = p( z < -20/20) = normalcdf(-100,-1) = .1587
\n" ); document.write( "P(x > 120) = P(z > -1) = normalcdf(-1,100) = .8413
\n" ); document.write( "P(x > 160) = P(z > 20/20)= normalcdf(1,100) = .1587 0r 15.87% ***
\n" ); document.write( ".5000 = .5000
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\n" ); document.write( "For the normal distribution: Below: z = 0, z = ± 1, z= ±2 , z= ±3 are plotted.
\n" ); document.write( "Area under the standard normal curve to the left of the particular z is P(z)
\n" ); document.write( "Note: z = 0 (x value: the mean) 50% of the area under the curve is to the left and 50% to the right
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