document.write( "Question 929018: Write the expression as an algebraic expression in x for x > 0.
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document.write( "3 sin(tan^−1 x)\r
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document.write( "Write the expression as an algebraic expression in x for x > 0.
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document.write( "3 tan(arccos x)\r
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document.write( "Write the expression as an algebraic expression in x for x > 0.
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document.write( "sec (sin^−1 x/ SquareRoot of(x^2 + 64)\r
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Algebra.Com's Answer #564182 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Write the expression as an algebraic expression in x for x > 0. \n" ); document.write( "3 sin(tan^−1 x) \n" ); document.write( "tanu=x/1(hypotenuse=√(x^2+1) \n" ); document.write( "3sinu=3(x/√(x^2+1)) \n" ); document.write( ".. \n" ); document.write( "Write the expression as an algebraic expression in x for x > 0. \n" ); document.write( "3 tan(arccos x) \n" ); document.write( "cosu=x \n" ); document.write( "sinu=√(1-cos^2(u))=√(1-x^2) \n" ); document.write( "3tanu=cos/sin=x/(√(1-x^2) \n" ); document.write( ".. \n" ); document.write( "Write the expression as an algebraic expression in x for x > 0. \n" ); document.write( "sec (sin^−1 x/ SquareRoot of(x^2 + 64) \n" ); document.write( "sinu=x/√(x^2+64) \n" ); document.write( "cosu=√(1-sin^2(u))=√(1-((x^2/(x^2+64))=64/(x^2+64) \n" ); document.write( "secu=1/cosu=(x^2+64)/64 \n" ); document.write( " |