document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=923179>Question 923179</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve 3y+3x=3 and 2y+6x=2 by substitution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #564162 by </B><A HREF=/tutors/aboutme.mpl?userid=Rongtian><B>Rongtian(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Rongtian><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=564162\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -2(3y+3x)=(3)-2 ... -6y-6x=-6<BR>\n" );
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document.write( "   -6y-6x=-6<BR>\n" );
document.write( "     2y+6x=2<BR>\n" );
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document.write( "    -4y=-4<BR>\n" );
document.write( "y=1\r<BR>\n" );
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document.write( "2(1)+6x=2<BR>\n" );
document.write( "x=0\r<BR>\n" );
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document.write( "x=0<BR>\n" );
document.write( "y=1 </SPAN>\n" );
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