document.write( "Question 929228: I need help with this one question is there anyone out there that is willing to help me?
\n" ); document.write( "The sum of the digits of a certain two-digit number is 12. Reversing its digits decreases the number by 18. What is the number...
\n" ); document.write( "Please us elimination of substitution. If not that's okay. Please show me your work:)
\n" ); document.write( "

Algebra.Com's Answer #564156 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
Let \"x\" = one's digit in original number
\n" ); document.write( "Let \"y\" = ten's digit in original number
\n" ); document.write( "value of original number = \"10y+%2B+x\"\r
\n" ); document.write( "\n" ); document.write( "In new number (with reversed digits):
\n" ); document.write( "\"y\" = one's digit
\n" ); document.write( "\"x\" = ten's digit
\n" ); document.write( "value of new number = \"10x+%2B+y\"\r
\n" ); document.write( "\n" ); document.write( "given: The sum of the digits of a certain two-digit number is \"12\". Reversing its digits decreases the number by \"18\".\r
\n" ); document.write( "\n" ); document.write( "We can now form these equations:
\n" ); document.write( "\"Sum of digits of two-digit no. is \"12\"\" (original number)\r
\n" ); document.write( "\n" ); document.write( "\"y+%2B+x+=+12\"...eq.1\r
\n" ); document.write( "\n" ); document.write( "\"Reverse the digits, the no. is decreased by \"18\".\"\r
\n" ); document.write( "\n" ); document.write( "\"10y+%2B+x+-+18+=+10x+%2B+y\"\r
\n" ); document.write( "\n" ); document.write( "\"10y+-+y+%2B+x+-18+=+10x+%2B+y+-+y\"\r
\n" ); document.write( "\n" ); document.write( "\"9y+%2B+x+-18+=+10x\"\r
\n" ); document.write( "\n" ); document.write( "\"9y+%2B+x+-+x+-18+=+10x+-+x\"\r
\n" ); document.write( "\n" ); document.write( "\"9y+-18=+9x\"\r
\n" ); document.write( "\n" ); document.write( "\"9y%2F9+-18%2F9+=+9x%2F9\"\r
\n" ); document.write( "\n" ); document.write( "\"y+-2=+x\"....eq.2\r
\n" ); document.write( "\n" ); document.write( "Now compare the two equations:\r
\n" ); document.write( "\n" ); document.write( "\"y+%2B+x+=+12\"
\n" ); document.write( "\"y+-2=+x\"\r
\n" ); document.write( "\n" ); document.write( "We can substitute \"%28y+-2%29\" for \"x\" in the first equation to solve:\r
\n" ); document.write( "\n" ); document.write( "\"y+%2B+%28y+-2%29+=+12\"\r
\n" ); document.write( "\n" ); document.write( "\"2y+-2=+12\"\r
\n" ); document.write( "\n" ); document.write( "\"2y+%2B+2+-+2+=+12+%2B2\"\r
\n" ); document.write( "\n" ); document.write( "\"2y+=+14\"\r
\n" ); document.write( "\n" ); document.write( "\"2y%2F2+=+14%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28y+=7%29\"\r
\n" ); document.write( "\n" ); document.write( "Now substitute this value for \"y\" into one of the equations to find \"x\":\r
\n" ); document.write( "\n" ); document.write( "\"y+-2+=+x\"\r
\n" ); document.write( "\n" ); document.write( "\"7-2+=+x\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x+=+5%29\"\r
\n" ); document.write( "\n" ); document.write( "Our original number is \"10y+%2B+x=highlight%2875%29\".
\n" ); document.write( "
\n" ); document.write( "
\n" );