document.write( "Question 929033: Please explain\r
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\n" ); document.write( "\n" ); document.write( "\"+%28sin+%28pi%2F4%29+cos+%28pi%2F6%29+-+sin+%28pi%2F6%29+cos+%28pi%2F4%29%29%5E2+\"
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Algebra.Com's Answer #564079 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
\"+%28sin+%28pi%2F4%29+cos+%28pi%2F6%29+-+sin+%28pi%2F6%29+cos+%28pi%2F4%29%29%5E2+\"
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\n" ); document.write( "rearrange terms:
\n" ); document.write( "\"%28sin%28pi%2F4%29cos%28pi%2F6%29-cos%28pi%2F4%29%29sin%28pi%2F6%29%5E2\"
\n" ); document.write( "Identity: sin(x-y)=sinxcosy-cosxsiny)
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\n" ); document.write( "(sin (pi/4)cos(pi/6)-sin(pi/6)cos(pi/4))^2=sin^2(π/12)
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