document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=929074>Question 929074</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Experiments have shown that on smooth, dry roads, the relationship between the braking distance(d) and speed(s) is given by d(s)=.03s^2. Speed given in miles/hour and the distance is in feet. How many feet should you leave between you can the car in front of you if you are driving the car at 55mi/hr? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #564070 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=564070\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  d(s)=.03s^2.<BR>\n" );
document.write( "d(55mph) = .03(55)^2 = 90.75 ft </SPAN>\n" );
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