document.write( "Question 928960: y varies directly with x. If y is -32 when x is 4, find x when y is -40 \n" ); document.write( "
Algebra.Com's Answer #564002 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "if \"y\" varies \"directly\" with \"x\", then there is a constant \"k\" such that \"y=k%2Ax\" \r
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\n" ); document.write( "\n" ); document.write( "if \"y=-32\" when \"x=4\", we can find the constant \"k\" \r
\n" ); document.write( "\n" ); document.write( "\"-32=k%2A4\" \r
\n" ); document.write( "\n" ); document.write( "\"-32%2F4=k\" \r
\n" ); document.write( "\n" ); document.write( "\"k=-8\" and our function is \"y=-8x\" \r
\n" ); document.write( "\n" ); document.write( "so, to find \"x\" when \"y=-40\" just plug known variable in \"y=-8x\"\r
\n" ); document.write( "\n" ); document.write( "\"-40=-8x\"...solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"-40%2F-8=x\"\r
\n" ); document.write( "\n" ); document.write( "\"x=40%2F8\"\r
\n" ); document.write( "\n" ); document.write( "\"x=5\"
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