document.write( "Question 78640: The square root of (6-x) + The square root of (5x + 6) = 6 \n" ); document.write( "
Algebra.Com's Answer #56392 by stanbon(75887)\"\" \"About 
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square root of (6-x) + The square root of (5x + 6) = 6
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "(6-x)+2sqrt[(6-x)(5x+6)]+5x+6 = 36
\n" ); document.write( "2sqrt[......] =24-4x
\n" ); document.write( "sqrt[....]=12-2x
\n" ); document.write( "Square both sides again to get:
\n" ); document.write( "-(5x+6)(x-6)=[-2(x-6)]^2
\n" ); document.write( "-[5x^2-24x-36] = 4[x^2-12x+36]
\n" ); document.write( "-5x^2+24x+36 = 4x^2-48x+144
\n" ); document.write( "-9x^2+72x-108=0
\n" ); document.write( "x^2-8x+12=0
\n" ); document.write( "(x-6)(x-2)=0
\n" ); document.write( "x=6 or x=2
\n" ); document.write( "Checking the answers for extraneous roots:
\n" ); document.write( "If x=6 the original equation is true
\n" ); document.write( "If x=2 the original equation is true
\n" ); document.write( "=================
\n" ); document.write( "cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
\n" );