document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=928861>Question 928861</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If you wanted to make 30 grams of sterling silver for a ring, how many grams of silver and copper would you need to start with? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #563911 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=563911\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> IF Using 92.5% by mass of silver and 7.5% copper<BR>\n" );
document.write( "30gm(.925) = 27.75gm Silver  and 2.25gm copper </SPAN>\n" );
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