document.write( "Question 928793: Please I would appreciate anyone's help. I am stuck on this problem.
\n" ); document.write( "Solve by elimination or substitution. For all three variables a, b and c. Use all three equations.
\n" ); document.write( "5a-5b+5c=25
\n" ); document.write( "-4a+4b-2c=-12
\n" ); document.write( "-a+ b-5c=-21
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Algebra.Com's Answer #563893 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
5a-5b+5c=25
\n" ); document.write( "-a+ b-5c=-21
\n" ); document.write( "4a - 4b = 4
\n" ); document.write( ".........5a-5b+5c=25 0r a-b+c= 5 ***
\n" ); document.write( "2(a-b+c= 5)
\n" ); document.write( "-4a+4b-2c=-12
\n" ); document.write( "-2a + 2b = -2
\n" ); document.write( ".......
\n" ); document.write( "4a - 4b = 4
\n" ); document.write( "2(-2a + 2b = -2)
\n" ); document.write( "0 = 0
\n" ); document.write( "Infinite Solutions: 4a - 4b = 4 0r a - b = 1
\n" ); document.write( "Re TY: Note: Using b = a-1
\n" ); document.write( "b = a-1, c = b-a+5 0r c = (a-1) - a + 5 = 4
\n" ); document.write( "(a, a-1, 4)
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