document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=78638>Question 78638</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A radiator contains 6 liters of a 25% antifreeze solution.  How much should be drained and replaced with pure antifreeze to produce a 33% antifreeze solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #56386 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=56386\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .25(6-x)+x=.33*6<BR>\n" );
document.write( "1.5-.25x+x=1.98<BR>\n" );
document.write( ".75x=1.98-1.5<BR>\n" );
document.write( ".75x=.48<BR>\n" );
document.write( "x=.48/.75<BR>\n" );
document.write( "x=.64 gallons of pure alcohol is needed to produce a 33% mixture.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( ".25(6-.64)+.64=.33*6<BR>\n" );
document.write( ".25*5.36+.64=1.98<BR>\n" );
document.write( "1.34+.64=1.98<BR>\n" );
document.write( "1.98=1.98 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );