document.write( "Question 928738: Can you show me a step-by-step process on how to factor this?
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Algebra.Com's Answer #563811 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"25-%28x%2B2%29%5E2+=+5%5E2-%28x%2B2%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E2-%28x%2B2%29%5E2\" is in the form \"a%5E2+-+b%5E2\" where \"a+=+5\" and \"b+=+x%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "use the formula \"a%5E2+-+b%5E2+=+%28a-b%29%28a%2Bb%29\" to get...\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2+-+b%5E2+=+%28a-b%29%28a%2Bb%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E2-%28x%2B2%29%5E2+=+%285-%28x%2B2%29%29%285%2B%28x%2B2%29%29\" Plug in \"a+=+5\" and \"b+=+x%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E2-%28x%2B2%29%5E2+=+%285-x-2%29%285%2Bx%2B2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E2-%28x%2B2%29%5E2+=+%283-x%29%287%2Bx%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"25-%28x%2B2%29%5E2+=+%283-x%29%287%2Bx%29\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore, \"25-%28x%2B2%29%5E2\" factors to \"%283-x%29%287%2Bx%29\" which is equivalent to \"-%28x-3%29%287%2Bx%29\" (I factored a negative out of \"3-x\" to get \"-%28x-3%29\")\r
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\n" ); document.write( "\n" ); document.write( "If you need more one-on-one help, email me at jim_thompson5910@hotmail.com. You can ask me a few more questions for free, but afterwards, I would charge you ($2 a problem to have steps shown or $1 a problem for answer only).\r
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\n" ); document.write( "\n" ); document.write( "Jim\r
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