document.write( "Question 928688: A boat travels 36 miles downstream in the same amount of time that it takes to travel 24 miles upstream. The boat travels at a still water rate that is 12 miles per hour more than the rate of the current. Find the rate of the current. \n" ); document.write( "
Algebra.Com's Answer #563771 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A boat travels 36 miles downstream in the same amount of time that it takes to travel 24 miles upstream. The boat travels at a still water rate that is 12 miles per hour more than the rate of the current. Find the rate of the current. \n" ); document.write( "----------------- \n" ); document.write( "Downstream DATA:: \n" ); document.write( "distance = 36 miles ; time = x hrs ; rate = d/t = 36/x mph \n" ); document.write( "-------- \n" ); document.write( "Upstream DATA: \n" ); document.write( "distance = 24 miles ; time = x hrs ; rate = d/t = 24/x mph \n" ); document.write( "------------------------ \n" ); document.write( "Equations: \n" ); document.write( "b + c = 36/x \n" ); document.write( "b - c = 24/x \n" ); document.write( "------ \n" ); document.write( "2b = (60/x) \n" ); document.write( "boat speed = 30/x \n" ); document.write( "------ \n" ); document.write( "2c = 12/x \n" ); document.write( "current speed = 6/x \n" ); document.write( "------ \n" ); document.write( "Equation \n" ); document.write( "boat speed = current speed + 12 \n" ); document.write( "30/x = 6/x + 12 \n" ); document.write( "24/x = 12 \n" ); document.write( "x = 2 \n" ); document.write( "---- \n" ); document.write( "Ans: current speed = 6/x = 6/2 = 3 mph \n" ); document.write( "------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------------- \n" ); document.write( " |