document.write( "Question 928688: A boat travels 36 miles downstream in the same amount of time that it takes to travel 24 miles upstream. The boat travels at a still water rate that is 12 miles per hour more than the rate of the current. Find the rate of the current. \n" ); document.write( "
Algebra.Com's Answer #563771 by stanbon(75887)\"\" \"About 
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A boat travels 36 miles downstream in the same amount of time that it takes to travel 24 miles upstream. The boat travels at a still water rate that is 12 miles per hour more than the rate of the current. Find the rate of the current.
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\n" ); document.write( "Downstream DATA::
\n" ); document.write( "distance = 36 miles ; time = x hrs ; rate = d/t = 36/x mph
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\n" ); document.write( "Upstream DATA:
\n" ); document.write( "distance = 24 miles ; time = x hrs ; rate = d/t = 24/x mph
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\n" ); document.write( "Equations:
\n" ); document.write( "b + c = 36/x
\n" ); document.write( "b - c = 24/x
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\n" ); document.write( "2b = (60/x)
\n" ); document.write( "boat speed = 30/x
\n" ); document.write( "------
\n" ); document.write( "2c = 12/x
\n" ); document.write( "current speed = 6/x
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\n" ); document.write( "Equation
\n" ); document.write( "boat speed = current speed + 12
\n" ); document.write( "30/x = 6/x + 12
\n" ); document.write( "24/x = 12
\n" ); document.write( "x = 2
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\n" ); document.write( "Ans: current speed = 6/x = 6/2 = 3 mph
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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