document.write( "Question 928658: Bradley has $25,000 that he wants to invest. He invests it in accounts paying 12%, 7%, and 6% simple interest. The account paying 12% is higher-risk account, so he wants the amount in that account to be half of the amount he has in the account paying 6% simple interest. If his annual interest is $1945, how much is invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #563770 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! .12x + .07(25000 - 3x) + .06(2x) = 1945 \n" ); document.write( ".12x - (.21x) + .12x = 1945 - 1750 \n" ); document.write( " .03x= 195 \n" ); document.write( "x = $6500, amount at 12% \n" ); document.write( "2x = $13,000, amount at 6% \n" ); document.write( " \n" ); document.write( "And..checking \n" ); document.write( "Sum = $25,000 \n" ); document.write( " \n" ); document.write( " |