document.write( "Question 928623: Solve the given equation in the interval [0,2pi].
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document.write( "The answer must be written as a multiple of pi. Give exact answers. Do not use decimal numbers. The answer must be an integer or a fraction.
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document.write( "2 (sin x)^2-5 cos x - 4 = 0.
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document.write( "Help would be appreciated dearly. \n" );
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Algebra.Com's Answer #563763 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 2 (sin x)^2-5 cos x - 4 = 0. \n" ); document.write( " ------ \n" ); document.write( "2(1-cos^2)-5cos - 4 = 0 \n" ); document.write( "------- \n" ); document.write( "2 - 2cos^2 - 5cos - 4 = 0 \n" ); document.write( "----- \n" ); document.write( "2cos^2 + 5cos +2 = 0 \n" ); document.write( "---- \n" ); document.write( "Factor:: \n" ); document.write( "(2cos+1)(cos+2) = 0 \n" ); document.write( "--- \n" ); document.write( "cos(x) = -1/2 or cos(x) = -2 \n" ); document.write( "------- \n" ); document.write( "cos(x) = -2 implies x = (2/3)pi or (4/3)pi \n" ); document.write( "---- \n" ); document.write( "cos(x) = -2 is extraneous \n" ); document.write( "============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------------- \n" ); document.write( " |