document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=78562>Question 78562</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation for x<BR>\n" );
document.write( "2^(x+4)=8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #56376 by </B><A HREF=/tutors/aboutme.mpl?userid=tutor_paul><B>tutor_paul(519)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutor_paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutor_paul><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=56376\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%5E%28x%2B4%29=8 ALIGN=MIDDLE  ALT=\"2%5E%28x%2B4%29=8\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Take the log of both sides of the equation. You can see<BR>\n" );
document.write( "that using log(base2) will be advantageous here:\r<BR>\n" );
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document.write( "log(base2)(2^(x+4))=log(base2)(8)\r<BR>\n" );
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document.write( "Use one of the algebraic property of logarithms to simplify left side:\r<BR>\n" );
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document.write( "(x+4)log(base2)(2)=log(base2)(8)\r<BR>\n" );
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document.write( "Taking the log(base2) of both of 2 and 8 allows further simplification:\r<BR>\n" );
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document.write( "(x+4)=3\r<BR>\n" );
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document.write( "Solve for x:\r<BR>\n" );
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document.write( "x=-1  </SPAN>\n" );
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