document.write( "Question 928638: May rides her bike the same distance that Leah walks. May rides her bike 10 km/h faster than Leah walks. If it takes May 1 h and Leah 3 h to travel that distance, how fast does each travel \n" ); document.write( "

Algebra.Com's Answer #563743 by TimothyLamb(4379) $\"\"$ $\"About$

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x = speed of leah
\n" ); document.write( "y = speed of may
\n" ); document.write( "---
\n" ); document.write( "y = x + 10
\n" ); document.write( "---
\n" ); document.write( "s = d/t
\n" ); document.write( "d = st
\n" ); document.write( "---
\n" ); document.write( "leah:
\n" ); document.write( "d = xt
\n" ); document.write( "d = 3x
\n" ); document.write( "---
\n" ); document.write( "may:
\n" ); document.write( "d = yt
\n" ); document.write( "d = 1y
\n" ); document.write( "---
\n" ); document.write( "equate the distances traveled:
\n" ); document.write( "3x = 1y
\n" ); document.write( "3x = y
\n" ); document.write( "3x = x + 10
\n" ); document.write( "2x = 10
\n" ); document.write( "x = 5
\n" ); document.write( "y = x + 10
\n" ); document.write( "y = 5 + 10
\n" ); document.write( "y = 15
\n" ); document.write( "---
\n" ); document.write( "answer:
\n" ); document.write( "x = speed of leah = 5 kph
\n" ); document.write( "y = speed of may = 15 kph
\n" ); document.write( "---
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