document.write( "Question 928589: A group of coworkers drove a car and a minivan to a conference. The car left first and traveled 50 mph. The minivan left 1/2 hour later and traveled at 60 mph. How long will it take the minivan to catch up to the car? \n" ); document.write( "
Algebra.Com's Answer #563699 by TimothyLamb(4379)\"\" \"About 
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distance traveled by the car when the minivan departs:
\n" ); document.write( "s = d/t
\n" ); document.write( "d = st
\n" ); document.write( "d = 50*0.5
\n" ); document.write( "d = 25 miles
\n" ); document.write( "---
\n" ); document.write( "speed of minivan relative to the car:
\n" ); document.write( "60 - 50 = 10 mph
\n" ); document.write( "---
\n" ); document.write( "time it will take the minivan to catch up to the car:
\n" ); document.write( "s = d/t
\n" ); document.write( "t = d/s
\n" ); document.write( "t = 25 miles / 10 mph
\n" ); document.write( "t = 2.5 hours
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