document.write( "Question 928576: The perimeter of a rectangle is 48 m. The length is 3 m less than twice the width. Find the length and the width. \n" ); document.write( "
Algebra.Com's Answer #563692 by TimothyLamb(4379)\"\" \"About 
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2L + 2W = 48
\n" ); document.write( "L = 2W - 3
\n" ); document.write( "---
\n" ); document.write( "2L + 2W = 48
\n" ); document.write( "2(2W - 3) + 2W = 48
\n" ); document.write( "4W - 6 + 2W = 48
\n" ); document.write( "6W = 48+6
\n" ); document.write( "W = (48+6)/6
\n" ); document.write( "W = 9
\n" ); document.write( "L = 2W - 3
\n" ); document.write( "L = 2*9 - 3
\n" ); document.write( "L = 15
\n" ); document.write( "---
\n" ); document.write( "answer:
\n" ); document.write( "W = 9 m
\n" ); document.write( "L = 15 m
\n" ); document.write( "---
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