document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=78586>Question 78586</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One of two complementary angles is 4 more than the other. Find the angles.<BR>\n" );
document.write( "(Recall that complementary angles are angles whose sum is equal to 90.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #56369 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=56369\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x= one complementary<BR>\n" );
document.write( "And x+4=the other \r<BR>\n" );
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document.write( "x+x+4=90 subtract 4 from both sides\r<BR>\n" );
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document.write( "x+x+4-4=90-4  collect like terms\r<BR>\n" );
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document.write( "2x=86  divide both sides by 2<BR>\n" );
document.write( "x=43 degrees------------------------------one angle<BR>\n" );
document.write( "x+4=43+4=47 degrees-----------------------------the other angle\r<BR>\n" );
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document.write( "CK\r<BR>\n" );
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document.write( "43+47=90<BR>\n" );
document.write( "90=90\r<BR>\n" );
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document.write( "also<BR>\n" );
document.write( "47 is 4 more than 43\r<BR>\n" );
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document.write( "Hope this helps ----ptaylor </SPAN>\n" );
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