document.write( "Question 78589: Two years ago a father was four times as old as his son. Three years from now the father will be only three times as old as the son. How old is each now?\r
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Algebra.Com's Answer #56365 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Let x=son's age now
\n" ); document.write( "Then x-2=son's age two years ago
\n" ); document.write( "And 4(x-2)=father's age two years ago
\n" ); document.write( "So 4(x-2)+2=4x-8+2=4x-6=father's age now
\n" ); document.write( "Also x+3=son's age three years for now
\n" ); document.write( "And 3(x+3)=father's age three years from now\r
\n" ); document.write( "\n" ); document.write( "Now if we subtract 5 years from father's age three years from now, then that will equal father's age two years ago. So:\r
\n" ); document.write( "\n" ); document.write( "3(x+3)-5=4(x-2) get rid of parens\r
\n" ); document.write( "\n" ); document.write( "3x+9-5=4x-8
\n" ); document.write( "3x+4=4x-8 subtract 4 and also 4x from both sides\r
\n" ); document.write( "\n" ); document.write( "3x-4x+4-4=4x-4x-8-4 collect like terms\r
\n" ); document.write( "\n" ); document.write( "-x=-12 divide both sides by -1
\n" ); document.write( "x=12-----------------------------------son's age now
\n" ); document.write( "4x-6=4*12-6=48-6=42-------------------------father's age now\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "Two years ago, father was 4 time as old as his son:
\n" ); document.write( "4(12-2)=42-2
\n" ); document.write( "40=40
\n" ); document.write( "also
\n" ); document.write( "Three years from now father will only be three times as old as his son\r
\n" ); document.write( "\n" ); document.write( "3(12+3)=42+3
\n" ); document.write( "45=45\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps------ptaylor\r
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