document.write( "Question 928500: According to a survey, only 15% of customers who visited the web site of a major retail store made a purchase. Random samples of size 50 are selected.
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document.write( "What is the average of all the sample proportions of customers who will make a purchase after visiting the web site?
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document.write( "What is the standard deviation of all the sample proportions of customers who will make a purchase after visiting the web site?
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document.write( " What proportion of the samples will have between 20% and 30% of customers who will make a purchase after visiting the web site?
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Algebra.Com's Answer #563649 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! According to a survey, only 15% of customers who visited the web site of a major retail store made a purchase. Random samples of size 50 are selected. \n" ); document.write( " What is the average of all the sample proportions of customers who will make a purchase after visiting the web site? \n" ); document.write( "Ans: 0.15 \n" ); document.write( "---------------------- \n" ); document.write( " What is the standard deviation of all the sample proportions of customers who will make a purchase after visiting the web site? \n" ); document.write( "Ans; sqrt[0.15*0.85/50] = 0.05 \n" ); document.write( "--------------------------- \n" ); document.write( " What proportion of the samples will have between 20% and 30% of customers who will make a purchase after visiting the web site? \n" ); document.write( "z(0.2) = (0.2-0.15)/0.05 = 0.05/0.05 = 1 \n" ); document.write( "z(0.3) = (0.3-0.15)/0.05 = 0.15/0.05 = 3 \n" ); document.write( "---- \n" ); document.write( "P(0.2 < p < 0.3) = P(1< z < 3) = 0.157 \n" ); document.write( "----------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------ \n" ); document.write( " \n" ); document.write( " |