document.write( "Question 928076: In an arithmetic series, t10=21 and t19=48 \r
\n" ); document.write( "\n" ); document.write( "Find a, d, and S23\r
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Algebra.Com's Answer #563617 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
I assume \"a\"= first term, \"t%5B10%5D\"= tenth term, \"t%5B19%5D\"= term number \"19\" , and \"S%5B23%5D\"= sum of first \"23\" terms.
\n" ); document.write( "It is commonly understood that \"d\"= common difference.
\n" ); document.write( "\"t%5Bn%5D=a%2B%28n-1%29d\" , so
\n" ); document.write( "\"system%2821=a%2B9d%2C48=a%2B18d%29\" --->\"48-21=18d-9d\"--->\"27=9d\"--->\"27%2F3=d\"--->\"highlight%28d=3%29\"
\n" ); document.write( "Then, \"system%2821=a%2B9d%2Cd=3%29\" --->\"21=a%2B9%2A3\"--->\"21=a%2B27\"--->\"21-27=a\"--->\"highlight%28a=-6%29\" .
\n" ); document.write( "There are different formulas to calculate sums of arithmetic sequences, but I prefer to remember that adding up the first \"n\" terms twice, grouping them in pairs \"head-to-tail\", \"t%5B0%5D%2Bt%5Bn%5D\" , \"t%5B1%5D%2Bt%5Bn-1%5D\" , \"t%5B2%5D%2Bt%5Bn-2%5D\" , and so on, you end up with a sum of \"n\" pairs that all add up to \"t%5B0%5D%2Bt%5Bn%5D\", so
\n" ); document.write( "\"2S%5Bn%5D=n%28t%5B0%5D%2Bt%5Bn%5D%29\"-->\"S%5Bn%5D=%28n%28t%5B0%5D%2Bt%5Bn%5D%29%29%2F2\" .
\n" ); document.write( "So, \"t%5B23%5D=-6%2B22%2A3=-6%2B66=60\" and .
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