document.write( "Question 928351: A total of $10,000 is invested in two funds paying 7% and 10% simple interest. (There is more risk in the 10% fund.) The combined annual interest for the two funds is $805. The system of equations that represents this situation is\r
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document.write( "x + y = 10,000
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document.write( "0.07x + 0.10y = 805\r
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document.write( "where x represents the amount invested in the 7% fund and y represents the amount invested in the 10% fund. Solve this system to determine how much of the $10,000 is invested at each rate.\r
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document.write( "7% Fund= $
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document.write( "10% Fund=$\r
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Algebra.Com's Answer #563590 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! Total amount of money invested: $10000 \n" ); document.write( "x+y=10000, \n" ); document.write( "Total yearly interest for the two accounts is: $805 \n" ); document.write( "0.07*x+0.10*y=805 \n" ); document.write( "x=10000-y \n" ); document.write( "Substitute for x \n" ); document.write( "0.07*(10000-y)+0.1*y=805 \n" ); document.write( "Multiply out \n" ); document.write( "700-0.07*y+0.1*y=805 \n" ); document.write( "Combine like terms. \n" ); document.write( "0.03*y=105 \n" ); document.write( "Isolate y \n" ); document.write( "y=$ 3500.00 at 10% earns $350 interest \n" ); document.write( "x=10000-y \n" ); document.write( "Calculate x \n" ); document.write( "x=$ 6500.00 at 7% earns $455 interest \n" ); document.write( "Check \n" ); document.write( "0.07*6500+0.1*3500=805 \n" ); document.write( "455+350=805 \n" ); document.write( "805=805 \n" ); document.write( "If 805=805 is TRUE and neither x nor y is negative then all is well \n" ); document.write( "codeint1 \n" ); document.write( " \n" ); document.write( " |