document.write( "Question 928351: A total of $10,000 is invested in two funds paying 7% and 10% simple interest. (There is more risk in the 10% fund.) The combined annual interest for the two funds is $805. The system of equations that represents this situation is\r
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\n" ); document.write( "\n" ); document.write( "x + y = 10,000
\n" ); document.write( "0.07x + 0.10y = 805\r
\n" ); document.write( "\n" ); document.write( "where x represents the amount invested in the 7% fund and y represents the amount invested in the 10% fund. Solve this system to determine how much of the $10,000 is invested at each rate.\r
\n" ); document.write( "\n" ); document.write( "7% Fund= $
\n" ); document.write( "10% Fund=$\r
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Algebra.Com's Answer #563590 by richwmiller(17219)\"\" \"About 
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Total amount of money invested: $10000
\n" ); document.write( "x+y=10000,
\n" ); document.write( "Total yearly interest for the two accounts is: $805
\n" ); document.write( "0.07*x+0.10*y=805
\n" ); document.write( "x=10000-y
\n" ); document.write( "Substitute for x
\n" ); document.write( "0.07*(10000-y)+0.1*y=805
\n" ); document.write( "Multiply out
\n" ); document.write( "700-0.07*y+0.1*y=805
\n" ); document.write( "Combine like terms.
\n" ); document.write( "0.03*y=105
\n" ); document.write( "Isolate y
\n" ); document.write( "y=$ 3500.00 at 10% earns $350 interest
\n" ); document.write( "x=10000-y
\n" ); document.write( "Calculate x
\n" ); document.write( "x=$ 6500.00 at 7% earns $455 interest
\n" ); document.write( "Check
\n" ); document.write( "0.07*6500+0.1*3500=805
\n" ); document.write( "455+350=805
\n" ); document.write( "805=805
\n" ); document.write( "If 805=805 is TRUE and neither x nor y is negative then all is well
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