document.write( "Question 928247: Bob wants to cut a wire that is 60 cm long into two pieces. Then he wants to make each piece into a square. Determine how the wire should be cut so that the total area of the two squares is as small as possible. \n" ); document.write( "
Algebra.Com's Answer #563579 by KMST(5328)\"\" \"About 
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Let \"x\" be the length of one of the pieces, in cm.
\n" ); document.write( "\"60-x\"= the length of the other piece, in cm.
\n" ); document.write( "The sides of the squares made will measure \"x%2F4\" and \"%2860-x%29%2F4\" cm,
\n" ); document.write( "and the areas of those squares, in square cm, will be
\n" ); document.write( "\"%28x%2F4%29%5E2=x%5E2%2F16\" and \"%28%2860-x%29%2F4%29%5E2=%283600-120x%2Bx%5E2%29%2F16\" respectively.
\n" ); document.write( "The total area of ththe two squares, in square cm, will be
\n" ); document.write( "
\n" ); document.write( "That expression, like \"x%5E2-60x%2B1800\" is a quadratic function of \"x\" .
\n" ); document.write( "Quadratic functions have the general form \"f%28x%29=ax%5E2%2Bbx%2Bc\" ,
\n" ); document.write( "and if \"a%3E0\" the quadratic function has a minimum at \"x=-b%2F2a\" .
\n" ); document.write( "Both, \"%28x%5E2-60x%2B1800%29%2F8\" and \"x%5E2-60x%2B1800\" , have a minimum at
\n" ); document.write( "\"x=-%28-60%29%2F2\"-->\"x=30\" .
\n" ); document.write( "So, to make the total area of the two squares is as small as possible, the wire should be cut in half, making two 30-cm pieces.
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