document.write( "Question 928171: Find the value of k so that the point (-2,10) is on the line y=kx-3k \n" ); document.write( "
Algebra.Com's Answer #563532 by TimothyLamb(4379)\"\" \"About 
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m = slope
\n" ); document.write( "---
\n" ); document.write( "use the point-slope form of the line with the given point (-2,10):
\n" ); document.write( "y - 10 = m(x + 2)
\n" ); document.write( "y = mx + 2m + 10
\n" ); document.write( "y = mx + (2m + 10)
\n" ); document.write( "---
\n" ); document.write( "equate to the given linear form:
\n" ); document.write( "kx - 3k = mx + (2m + 10)
\n" ); document.write( "---
\n" ); document.write( "equate \"like\" terms:
\n" ); document.write( "---
\n" ); document.write( "equate the x terms:
\n" ); document.write( "mx = kx
\n" ); document.write( "m = k
\n" ); document.write( "k = m
\n" ); document.write( "---
\n" ); document.write( "equate the constant terms:
\n" ); document.write( "-3k = (2m + 10)
\n" ); document.write( "k = (2m + 10)/-3
\n" ); document.write( "---
\n" ); document.write( "equate the k expressions:
\n" ); document.write( "m = (2m + 10)/-3
\n" ); document.write( "-3m = 2m + 10
\n" ); document.write( "-5m = 10
\n" ); document.write( "m = -2
\n" ); document.write( "---
\n" ); document.write( "answer:
\n" ); document.write( "k = -2
\n" ); document.write( "---
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