document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=928158>Question 928158</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Thanks for the help but now  confused because 2 separate people gave me 2 different solutions... Please help. Cathy is 16 years younger than Mary. In 5 years Mary will be twice as old as Cathy. Find their ages now. Is it 11 and 27 or 21 and 37??? Both suruons seem correct. I got 11 and 27 before I asked for help but now I'm worried it's wrong? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #563504 by </B><A HREF=/tutors/aboutme.mpl?userid=scorp79><B>scorp79(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scorp79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scorp79><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=563504\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The answer is 11 and 27<BR>\n" );
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document.write( "Mary 27(current age)+ 5(years later)=32<BR>\n" );
document.write( "Cathy 11(current age)+ 5(years later)=16<BR>\n" );
document.write( "16*2=32 (twice as old)(age of Mary 5 years later) </SPAN>\n" );
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