document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=928118>Question 928118</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Eight coins containing nickels, dimes and quarters equal $1.00.  There are twice as many dimes as quarters.  There are the same number of nickels as there are quarters. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #563476 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=563476\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here's a similar problem:<BR>\n" );
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document.write( "A man has 52 coins, all of which are dimes, quarters, and nickels. The total value of his change is $8.20. If the number of quarters is twice the number of nickels, how many of each does he have?<BR>\n" );
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document.write( "Use d, q & n, makes it clearer<BR>\n" );
document.write( "d + q + n = 52<BR>\n" );
document.write( "10d + 25q + 5n = 820<BR>\n" );
document.write( "q = 2n<BR>\n" );
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document.write( "Sub for q in the 1st 2 eqns<BR>\n" );
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document.write( "d + 3n = 52 times 2 --> 2d + 6n = 104<BR>\n" );
document.write( "10d + 50n + 5n = 820<BR>\n" );
document.write( "10d + 55n = 820 /5 --> 2d + 11n = 164<BR>\n" );
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document.write( "2d + 6n = 104<BR>\n" );
document.write( "2d + 11n = 164<BR>\n" );
document.write( "------------------- Subtract<BR>\n" );
document.write( "-5n = -60<BR>\n" );
document.write( "n = 12 nickels<BR>\n" );
document.write( "etc </SPAN>\n" );
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