document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=928114>Question 928114</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this: A man has 52 coins, all of which are dimes, quarters, and nickels. The total value of his change is $8.20. If the number of quarters is twice the number of nickels, how many of each does he have?\r<BR>\n" );
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document.write( "So far I have two equations set up: x+2y+z=52 and 0.10x +0.25y +0.05z=8.20<BR>\n" );
document.write( "but I don't think those are right.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #563468 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=563468\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the number of nickels and y be the number dimes, then we have<BR>\n" );
document.write( "2x +x +y = 52<BR>\n" );
document.write( ".25(2x) + .05x + .10y = 8.20<BR>\n" );
document.write( "solve first equation for y<BR>\n" );
document.write( "y = 52 -3x<BR>\n" );
document.write( "substitute for y in second equation<BR>\n" );
document.write( ".25(2x) + .05x + .10(52-3x) = 8.20<BR>\n" );
document.write( ".50x + .05x + 5.20 - .30x = 8.20<BR>\n" );
document.write( ".25x = 3.00<BR>\n" );
document.write( "x = 12<BR>\n" );
document.write( "therefore,<BR>\n" );
document.write( "there are 24 quarters, 12 nickels, 16 dimes<BR>\n" );
document.write( "now check the answers<BR>\n" );
document.write( "24*.25 + 12*.05 + 16*.10 = 8.20<BR>\n" );
document.write( "6.00 + .60 + 1.60 = 8.20<BR>\n" );
document.write( "8.20 = 8.20<BR>\n" );
document.write( "answer checks  :-)<BR>\n" );
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