document.write( "Question 78565: Please help me solve this equation. \"+4c-7=2c-1+\"\r
\n" ); document.write( "\n" ); document.write( "This is as far as I got. \"+4c-7=2c-1+\"
\n" ); document.write( " \"+4c-7%2B7=2c-1%2B7+\"
\n" ); document.write( " \"+4c=2c-8+\"\r
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\n" ); document.write( "\n" ); document.write( " - Thank-you and I hope you can help me
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Algebra.Com's Answer #56345 by nihon64(5)\"\" \"About 
You can put this solution on YOUR website!
4c-7=2c-1\r
\n" ); document.write( "\n" ); document.write( "Since 2c contains the variable to solve for, move it to the left-hand side of the equation by subtracting 2c from both sides.
\n" ); document.write( "4c-7-2c=-1\r
\n" ); document.write( "\n" ); document.write( "Since 4c and -2c are like terms, add -2c to 4c to get 2c.
\n" ); document.write( "2c-7=-1\r
\n" ); document.write( "\n" ); document.write( "Since -7 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 7 to both sides.
\n" ); document.write( "2c=7-1\r
\n" ); document.write( "\n" ); document.write( "Subtract 1 from 7 to get 6.
\n" ); document.write( "2c=6\r
\n" ); document.write( "\n" ); document.write( "Divide each term in the equation by 2.
\n" ); document.write( "(2c)/(2)=(6)/(2)\r
\n" ); document.write( "\n" ); document.write( "Simplify the left-hand side of the equation by canceling the common terms.
\n" ); document.write( "c=(6)/(2)\r
\n" ); document.write( "\n" ); document.write( "Simplify the right-hand side of the equation by simplifying each term.
\n" ); document.write( "c=3\r
\n" ); document.write( "\n" ); document.write( "Hope that helps!
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