document.write( "Question 928018: Two bicyclists leave a rest stop going in the same direction. Bicyclist A travels at 20 mph and bicyclist B travels at 15 mph. B leaves 3 hours before A. After how many miles will A catch up to B? \n" ); document.write( "
Algebra.Com's Answer #563428 by TimothyLamb(4379)\"\" \"About 
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s = d/t
\n" ); document.write( "d = st
\n" ); document.write( "t = d/s
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\n" ); document.write( "speed of A relative to B:
\n" ); document.write( "s = 20 - 15 = 5 mph
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\n" ); document.write( "distance traveled by B when A departs:
\n" ); document.write( "d = 15*3 = 45 miles
\n" ); document.write( "---
\n" ); document.write( "time traveled by A when he catches B:
\n" ); document.write( "t = 45/5 = 9 hours
\n" ); document.write( "---
\n" ); document.write( "distance traveled by A when he catches B:
\n" ); document.write( "d = 20*9 = 180 miles
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