document.write( "Question 928052: Two factory plants are making TV panels. Yesterday, Plant A produced 6000 panels. Ten percent of the panels from Plant A and 3% of the panels from Plant B were defective. How many panels did Plant B produce, if the overall percentage of defective panels from the two plants was 6% ? \n" ); document.write( "

Algebra.Com's Answer #563418 by TimothyLamb(4379) $\"\"$ $\"About$

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x = panels produced by plant A = 6000
\n" ); document.write( "y = panels produced by plant B = ?
\n" ); document.write( "---
\n" ); document.write( "0.1x + 0.03y = 0.06(x + y)
\n" ); document.write( "0.1*6000 + 0.03y = 0.06(6000 + y)
\n" ); document.write( "600 + 0.03y = 0.06*6000 + 0.06y
\n" ); document.write( "0.06y - 0.03y = 600 - 360
\n" ); document.write( "0.03y = 600 - 360
\n" ); document.write( "y = (600 - 360)/0.03
\n" ); document.write( "y = 8000
\n" ); document.write( "---
\n" ); document.write( "answer:
\n" ); document.write( "y = panels produced by plant B = 8000
\n" ); document.write( "---
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