document.write( "Question 928040: Hey guys, I was wondering if you guys could help me or guide me thru these questions, thanks for your time. \r
\n" ); document.write( "\n" ); document.write( "The half-life of radioactive plutonium-238 is 87.7 years. If ten grams are present now:\r
\n" ); document.write( "\n" ); document.write( "a) Build an exponential function that models the amount of plutonium-238 after t years.
\n" ); document.write( "b) Use your function to determine the amount of plutonium-238 remaining after 200 years. Solve this algebraically.
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Algebra.Com's Answer #563415 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
given:\r
\n" ); document.write( "\n" ); document.write( "the half-life of radioactive plutonium-238 is \"87.7\" years\r
\n" ); document.write( "\n" ); document.write( "and starting amount \"10gr\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "a) Build an exponential function that models the amount of plutonium-238 after \"t\" years.\r
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\n" ); document.write( "\n" ); document.write( "\"A=A%5Bo%5D%280.5%29%5E%28t%2F87.7+%29\" ...where \"A\" - amount after \"t\" years , \"A%5Bo%5D\" -amount started with\r
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\n" ); document.write( "\n" ); document.write( "b) Use your function to determine the amount of plutonium-238 remaining after \"200\" years. Solve this algebraically.\r
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\n" ); document.write( "\n" ); document.write( "\"A%5Bo%5D=10gr\"
\n" ); document.write( "\"t=200\" years\r
\n" ); document.write( "\n" ); document.write( "\"A=10%280.5%29%5E%28%28200cross%28years%29%29%2F%2887.7cross%28years%29%29+%29\"...since exponent is not visible here, it is \"%28200cross%28years%29%29%2F%2887.7cross%28years%29%29=2.280501710376283+\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=10gr%280.5%29%5E%282.280501710376283+%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"A=10gr%280.205826%29\"\r
\n" ); document.write( "\n" ); document.write( "\"A=2.05826gr\"\r
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