document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=927982>Question 927982</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a plant has a pollution control system shutdown once every 75 days, on average. What is the probability of at least one shutdown in the next year? give the answer to one decimal place.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #563392 by </B><A HREF=/tutors/aboutme.mpl?userid=428225><B>428225(90)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=428225><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=428225><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=563392\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 365/75= (n)\r<BR>\n" );
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document.write( "1*4.866... (The 6 is recurring)\r<BR>\n" );
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document.write( "4.866.. = rate per year\r<BR>\n" );
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document.write( "Then use the formula (e^-n*n^r)/(r!)\r<BR>\n" );
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document.write( "So now you want the probability of getting no shutdowns\r<BR>\n" );
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document.write( " (e^-4.86..*4.86..^0)/(0!) = P(0)\r<BR>\n" );
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document.write( "1-P(0) =………\r<BR>\n" );
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document.write( "You can do this part for yourself.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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