document.write( "Question 927995: There are ten questions on a test. The instruction say that only seven of the questions are to be answered. How many ways can the seven to be answered be selected? Hint: The order in which the seven questions are answered is not important. All that matters is which seven are eventually answered. \n" ); document.write( "
Algebra.Com's Answer #563381 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
This is the same as asking \"How many ways are there to pick 3 questions to NOT answer\". This is easier because 3 is less than 7. Let's say we have 3 slots for the 3 questions we don't answer.\r
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\n" ); document.write( "\n" ); document.write( "10 problems to choose from for slot 1
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\n" ); document.write( "8 problems to choose from for slot 3\r
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\n" ); document.write( "\n" ); document.write( "10*9*8 = 720 ways to pick 3 problems where order matters\r
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\n" ); document.write( "\n" ); document.write( "Divide by 3! = 3*2*1 = 6 to get 720/6 = 120\r
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\n" ); document.write( "\n" ); document.write( "There are 120 ways to select 3 problems that will NOT be attempted. The other 7 will be done.\r
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\n" ); document.write( "\n" ); document.write( "So there are 120 ways to pick 7 problems where order doesn't matter. The final answer is 120\r
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\n" ); document.write( "\n" ); document.write( "Notice how 10 C 7 = 10 C 3 = 120 and how this symmetry shows up in Pascal's Triangle.\r
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\n" ); document.write( "\n" ); document.write( "If you need more one-on-one help, email me at jim_thompson5910@hotmail.com. You can ask me a few more questions for free, but afterwards, I would charge you ($2 a problem to have steps shown or $1 a problem for answer only).\r
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