document.write( "Question 927944: solve the system by the method of substitution
\n" ); document.write( "x=y+3
\n" ); document.write( "x=y^2+1
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Algebra.Com's Answer #563373 by MathLover1(20850)\"\" \"About 
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\"x=y%2B3\".....eq.1
\n" ); document.write( "\"x=y%5E2%2B1\"...eq.2
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\n" ); document.write( "\n" ); document.write( "\"x=y%5E2%2B1\"...eq.2 substitute \"x=y%2B3\"\r
\n" ); document.write( "\n" ); document.write( "\"y%2B3=y%5E2%2B1\"...solve for \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"0=y%5E2-y-3%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"y%5E2-y-2=0\"\r
\n" ); document.write( "\n" ); document.write( "\"y%5E2%2By-2y-2=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28y%5E2%2By%29-%282y%2B2%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"y%28y%2B1%29-2%28y%2B1%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28y-2%29%28y%2B1%29=0\"\r
\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "if \"%28y-2%29=0\"=> \"y=2\"\r
\n" ); document.write( "\n" ); document.write( "if \"%28y%2B1%29=0\"=> \"y=-1\"\r
\n" ); document.write( "\n" ); document.write( "now find \"x\":\r
\n" ); document.write( "\n" ); document.write( "\"x=y%2B3\".....eq.1 if \"y=2\"\r
\n" ); document.write( "\n" ); document.write( "\"x=2%2B3\"\r
\n" ); document.write( "\n" ); document.write( "\"x=5\"\r
\n" ); document.write( "\n" ); document.write( "\"x=y%2B3\".....eq.1 if \"y=-1\"\r
\n" ); document.write( "\n" ); document.write( "\"x=-1%2B3\"\r
\n" ); document.write( "\n" ); document.write( "\"x=2\"\r
\n" ); document.write( "\n" ); document.write( "so, your solutions are:\r
\n" ); document.write( "\n" ); document.write( "(\"5\",\"2\")\r
\n" ); document.write( "\n" ); document.write( "and\r
\n" ); document.write( "\n" ); document.write( "(\"2\",\"-1\")\r
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