document.write( "Question 927926: Having trouble with this one...\r
\n" ); document.write( "\n" ); document.write( "Find the focus of the parabola: 8x+3y^2 = 12
\n" ); document.write( "

Algebra.Com's Answer #563367 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Find the focus of the parabola: 8x+3y^2 = 12
\n" ); document.write( "3y^2=-8x+12
\n" ); document.write( "3y^2=-8(x-3/2)
\n" ); document.write( "y^2=-(8/3)(x-3/2)
\n" ); document.write( "This is an equation of a parabola that open leftwards;.
\n" ); document.write( "Its basic form of equation:(y-k)^2=4p(x-h), (h,k)=coordinates of the vertex
\n" ); document.write( "For given problem:
\n" ); document.write( "vertex:(3/2,0)
\n" ); document.write( "axis of symmetry: x-axis or y=0
\n" ); document.write( "4p=8/3
\n" ); document.write( "p=8/12=2/3
\n" ); document.write( "focus:((3/2-2/3),0)=(5/6,0) (p-distance left of vertex on the axis of symmetry)
\n" ); document.write( "
\n" );