document.write( "Question 927926: Having trouble with this one...\r
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document.write( "Find the focus of the parabola: 8x+3y^2 = 12 \n" );
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Algebra.Com's Answer #563367 by lwsshak3(11628) ![]() You can put this solution on YOUR website! Find the focus of the parabola: 8x+3y^2 = 12 \n" ); document.write( "3y^2=-8x+12 \n" ); document.write( "3y^2=-8(x-3/2) \n" ); document.write( "y^2=-(8/3)(x-3/2) \n" ); document.write( "This is an equation of a parabola that open leftwards;. \n" ); document.write( "Its basic form of equation:(y-k)^2=4p(x-h), (h,k)=coordinates of the vertex \n" ); document.write( "For given problem: \n" ); document.write( "vertex:(3/2,0) \n" ); document.write( "axis of symmetry: x-axis or y=0 \n" ); document.write( "4p=8/3 \n" ); document.write( "p=8/12=2/3 \n" ); document.write( "focus:((3/2-2/3),0)=(5/6,0) (p-distance left of vertex on the axis of symmetry) \n" ); document.write( " |