document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=78588>Question 78588</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of the base of an isosceles triangle is 4 inches less than the length of one of the two equal sides of the triangles. If the perimeter is 32, find the three sides of the triangle.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #56336 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=56336\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET X=THE EQUAL SIDES.<BR>\n" );
document.write( "THEN THE BASE=X-4.<BR>\n" );
document.write( "THE PERIMETER IS THE SUM OF ALL THREE SIDES.<BR>\n" );
document.write( "THUS WE HAVE THE FOLLOWING EQUATION FOR THE PERIMETER<BR>\n" );
document.write( "X+X+(X-4)=32<BR>\n" );
document.write( "3X-4=32<BR>\n" );
document.write( "3X=32+4<BR>\n" );
document.write( "3X=36 <BR>\n" );
document.write( "X=36/3<BR>\n" );
document.write( "X=12 FOR THE EQUAL SIDES.<BR>\n" );
document.write( "THUS THE BASE=12-4=8<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "32=12+12+8<BR>\n" );
document.write( "32=32  </SPAN>\n" );
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