document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=78602>Question 78602</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me help my daughter with rational expressions.\r<BR>\n" );
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document.write( " x+1 over (x+3)(x-3)plus 4(x-3) over (x+3)(x-3)plus (x-1)(x-3) over (3-x)(x+3) =?\r<BR>\n" );
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document.write( "Also,\r<BR>\n" );
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document.write( " 6 over x-y plus 4x over y^2 - x^2  =?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #56335 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=56335\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x+1)/(x+3)(x-3) + 4(x-3) / (x+3)(x-3) + (x-1)(x-3) / (3-x)(x+3) <BR>\n" );
document.write( "Adjust the 3rd term so it has the same denominator as the 1st and 2nd terms.<BR>\n" );
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document.write( "=(x+1)/(x+3)(x-3) + 4(x-3) / (x+3)(x-3) - (x-1)(x-3) / (x-3)(x+3) <BR>\n" );
document.write( "Combine the numerators over a single denominator, as follows:\r<BR>\n" );
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document.write( "=[x+1+4x-12-x^2+4x-3]/[(x-3)(x+3)]\r<BR>\n" );
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document.write( "=[-(x^2-9x+2]/[(x-3)(x+3)]\r<BR>\n" );
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document.write( "Also,\r<BR>\n" );
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document.write( " 6 /(x-y) + 4x/(y^2 - x^2)<BR>\n" );
document.write( "=6 /(x-y) - 4x/(x^2 - y^2)  <BR>\n" );
document.write( "The least common denominator is (x-y)(x+y)<BR>\n" );
document.write( "=6(x+y)/lcm - 4x/lcm<BR>\n" );
document.write( "=[6x+6y-4x]/lcm<BR>\n" );
document.write( "=[2x+6y]/[(x-y)(x+y)]<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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