document.write( "Question 927909: How many gallons of a 21% acid solution and the 29% acid solution need to be mixed to make 8 gallons of a 26% acid solution? \n" ); document.write( "
Algebra.Com's Answer #563323 by Techpriest(29)![]() ![]() ![]() You can put this solution on YOUR website! Assuming we don't know the gallons of the 21% acid solution, we will express it as x. \n" ); document.write( "Assuming we don't know the gallons of the 29% acid solution, we will express it as y. \n" ); document.write( "In the assumptions, we are able to convey this equation. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "We are able to solve it through substitution by finding that y = 8 - x through the subtraction property of equality. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now we know that x is 3, we will plug-in the x for the y to find the value of y. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It takes 3 gallons of a 21% acid solution and 5 gallons of a 29% acid solution to make 8 gallons of a 26% acid solution. \n" ); document.write( " |