document.write( "Question 927869: The average household income per year is μ = $ 15,000. For a random sample of 15 households in the area, the mean x-bar = 14,000 with a sample standard deviation of s = $2,000. Test the hypothesized value of the mean at the 5 percent level of significance. \n" ); document.write( "
Algebra.Com's Answer #563308 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! Previously Posted \n" ); document.write( "Ho: u = $15,000 (claim) \n" ); document.write( "Ha: u ≠ $15,000 \n" ); document.write( "...... \n" ); document.write( "Sample: n = 15 \n" ); document.write( " mean x-bar = 14,000 with a sample standard deviation of s = $2,000 \n" ); document.write( "....... \n" ); document.write( "Test statistic: (14000-15000)/(2000/sqrt(15)) = -1.9365 \n" ); document.write( "p-value: p( z < -1.9365) = normalcdf(-100, -1.9365) = .0264 \n" ); document.write( ".......... \n" ); document.write( ".05 level of significance.... \n" ); document.write( ".0264 < .05, Reject Ho. \n" ); document.write( "The test results do NOT support the claim that u = $15,000 \n" ); document.write( " |