document.write( "Question 927869: The average household income per year is μ = $ 15,000. For a random sample of 15 households in the area, the mean x-bar = 14,000 with a sample standard deviation of s = $2,000. Test the hypothesized value of the mean at the 5 percent level of significance. \n" ); document.write( "
Algebra.Com's Answer #563308 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Ho: u = $15,000 (claim)
\n" ); document.write( "Ha: u ≠ $15,000
\n" ); document.write( "......
\n" ); document.write( "Sample: n = 15
\n" ); document.write( " mean x-bar = 14,000 with a sample standard deviation of s = $2,000
\n" ); document.write( ".......
\n" ); document.write( "Test statistic: (14000-15000)/(2000/sqrt(15)) = -1.9365
\n" ); document.write( "p-value: p( z < -1.9365) = normalcdf(-100, -1.9365) = .0264
\n" ); document.write( "..........
\n" ); document.write( ".05 level of significance....
\n" ); document.write( ".0264 < .05, Reject Ho.
\n" ); document.write( "The test results do NOT support the claim that u = $15,000
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